Discussed here are the discontinuous conduction mode, mode boundary, and conversion ratio of simple converters.
Origin of the Discontinuous Conduction Mode
During continuous conduction mode, the
inductor current in the energy transfer never reaches zero value. In the
case of the discontinuous conduction mode, the inductor current falls
to zero level which is very common in DC-to-DC converters.
If the peak of the inductor current
ripples is less than the DC component of the inductor current, the diode
current is always positive and the diode is forced to turn on when the
switch S (either a transistor or thyristor) is off. On the other hand,
if the peak of the inductor current ripples becomes more than the DC
component of the inductor current, the total current falls to zero value
while the diode is conducting. Thus, the diode will stop conducting and
the inductor current will remain at zero value until the switch S will
be gated again due to the polarity reversal across the switch. This
gives rise to the discontinuous conduction mode in the chopper or the
DC-to-DC converter.
In the discontinuous conduction mode,
inductor current is not persistent throughout the complete cycle and
reaches zero level earlier even before the end of the period.
Discontinuous conduction mode inductance is less than the minimum value
of the inductance for the continuous conduction mode,
LDCM < LCCM.
Thus, this condition generally arises for the light-load condition.
Let the value of inductance in the case of the discontinuous conduction mode be,
LDCM=ξ LCCM where 0<ξ<1 conduction.="" discontinuous="" for="" nbsp="" p="" the="">
IL+=1L∫t0(VS−VO)dt+Imin
⇒IL+=VS−VOLt+Imin
Imax=VS−VOLDT+Imin
IL−=(1L)∫tDT−VOdt+Imax
⇒IL−=VOL(DT−t)+Imin
Iavg=VOR.
(Area)L=TImin+12T(Imax−Imin)
Iavg=VOR=Imin+12(Imax−Imin)
Iavg=VS−VO2LDT+Imin
⇒Iavg=D(VS−VO)2Lf+Imin=VOR
L=D(VS−VO)R2f(VO−IminR)
The discontinuous conduction mode usually
occurs in converters which consist of single-quadrant switches and may
also occur in converters with two-quadrant switches. Two-level DC buck,
and boost and buck-boost converters will be discussed further in this
article. There are two levels indicated here towards the two-voltage
level for the inductor voltage.
The energy stored in the inductor is
proportional to the square of the current flowing through it. Having the
same power through the converter, the requirement of the inductor
current is higher in the case of the discontinuous conduction as
compared to the continuous conduction mode. This causes more losses in
the circuit of the discontinuous conduction. As the energy stored is not
yet released to the output in the discontinuous conduction, the output
gets affected by the ringing. This may also cause a noise in the
discontinuous conduction mode.
Moreover, the value of the inductance
required for discontinuous conduction mode is lesser as compared to the
continuous conduction mode since it allows the fall of the inductor
current to zero level. This causes higher values for the
root-mean-square and the peak current. Thus, the size of the
transformer required in isolated converters is bigger as compared to
the continuous-conduction transformer size to suit the larger flux
linkage and the losses.
Conversion ratio is independent of the
load during the continuous conduction mode but when it enters in
discontinuous conduction mode, it becomes dependent to the load. This
complicates the DC-circuit analysis because the first-order equations
become second order.
In most of the applications, continuous
conduction mode is employed. Yet, discontinuous conduction mode can also
be used for certain applications such as for the low-current and
loop-compensation applications.
Buck Converter
Consider the simple buck converter circuit
shown in Fig. 1. The current in the converter is controlled here by two
switches labeled as S (MOSFET) and D (Diode).
This is a single-quadrant converter with the following waveforms for the continuous conduction mode shown in Fig. 2.
Figure 2. Supply Current IS, Diode Current ID, Inductor Current I, and Inductor Voltage VL Waveforms respectively (Buck Converter)
The buck converter in discontinuous and
continuous conduction modes are in the second-order and first-order
systems respectively.
For continuous conduction mode,
For 0≤t≤DT.
At t=DT, inductor current is at maximum value,
[Equation 1]
For DT≤t≤T.
The average value of the inductor current for the buck converter is
Because the inductor is always connected to the load whether the switch is on or off.
The average value of the current through the capacitor is nil due to the capacitor charge balance condition.
From Fig. 2, the area under the inductor current waveform is,
Average value of the inductor current is,
[Equation 2]
From Equations 1 and 2 we can get,
The value of inductance is,
The boundary of continuous condition is when Imin=0. If the value of Imin<0 conduction="" converter="" discontinuous="" enters="" in="" mode.="" p="" the="">
LCCM=D(VS−VO)R2fVO
L=LDCM=ξLCCM=ξD(VS−VO)R2fVO,
1>
Thus,
L=LCCM for Imin=0
Hence,
The value of inductance for the discontinuous conduction is given by
where 0<ξ<1 .="" p="">
⇒DTVS+(TX−DT).(VS−VO)=0
⇒TX=DVO(VS−VO)f
Imax=VSLTON=VSLfD
Iavg=11−DVOR=12TXImaxT
⇒VOR=(12)(DVO(VS−VO)f)(VSDLf)(1−D)T
D=2(VO−VS)LfRYVS−−−−−−−−−−−−√
[Equation 18]
VO−VSVS.
LDCM=ξYRVS(VO−VS)2fVO
D=VO−VSVOξ√
⇒VOVS=VS1−Dξ√
Iavg=YIO=YVOR=(1−D)VOR
1>
0>
For discontinuous conduction mode, when L< LCCM, the waveforms for the inductor current and inductor voltage are shown in Fig.3.
Figure 3. Inductor Current and Voltage for the Discontinuous Conduction Mode of Buck Converter
It is clear from the Fig.3 that the value of the minimum inductor current is zero i.e. Imin=0.
As the current across the inductor current is reduced to zero, the value of the voltage across the inductor is also reduced to zero value while VC =VO during the entire cycle.
For the time duration 0 ≤ t ≤ TON
IL+(t)=VS−VOLt
[Equation 3]
As the value of the peak inductor current occurs at t = TON,
⇒Imax=VS−VOLTON=VS−VOLDT=VS−VOLfD.
For the time duration TON ≤ t ≤ TX,
IL−(t)=∫tTON−VCLdt+Imax
⇒IL−(t)=VCL(TON−t)+VS−VOLf
[Equation 4]
At t = TX, current reduces to zero value,
0=VCL(TON−TX)+VS−VOLf
⇒TX=DVSfVO
Compared to the continuous condition, the amount of energy needed by the load is lesser in the discontinuous condition.
It is considered that the converter is operated in the steady state. Thus, the energy in the inductor remains the same at the start and at the end of the cycle. The volt-time balance condition can also be applied here.
The above equation can also be derived using the inductor volt-second balance condition as,
(VS−VC)TON+(−VC)(TX−TON)=0
⇒(VS−VC)DT+(−VC)(TX−DT)=0
⇒TX=VSDfVO
For the time duration TX ≤ t ≤ T
IL0(t)=0
From the Fig. 3, it is clear that the average value of the inductor current is equal to the area under the load current curve divided by T.
Iavg=12TXImaxT
For the DC supply,
Iavg=VOR
Hence,
VOR=VS(VS−VO)D22LVOf
The duty cycle ratio for the discontinuous conduction mode in the case of the buck converter is,
D=VO2LfRVS(VS−VO)−−−−−−−−−−−−√
[Equation 5]
The duty cycle ratio of the buck converter in its continuous conduction mode is
D=VOVi.
The duty cycle ratio for the buck converter is also dependent on the inductance L, load resistance R, and the switching frequency f.
For discontinuous conduction mode,
L=LDCM=ξLCCM=ξD(VS−VO)R2fVO
[Equation 6]
Substitution of the Equation 5 into Equation 6 gives,
D=VOVSξ√
[Equation 7]
Since 0 < ξ < 1, duty cycle ratio of the buck converter in the discontinuous conduction mode is less than its value in the continuous conduction mode. Thus, less amount of energy is transferred through the converter which is not enough to maintain the inductor current throughout the entire period. This is the reason the discontinuous current flows through the inductor.
The conversion ratio of buck DC-to-DC converter is,
VOVS=Dξ√
where 0<ξ<1 div="">
If the value of ξ is greater than 1, the converter enters in the continuous conduction mode. We can easily know the conduction state of the buck converter, which is either continuous or discontinuous, if we know the value of input and output voltages of the converter by simply measuring the value of ξ.
Instantaneous value of the capacitor current is given by subtracting the value of the inductor current to the load current. When the inductor current value is reduced to zero value, the load current is supplied by the capacitor.
From Equations 3 and 4 we can get:
For the time duration 0 < t
IC+(t)=VS−VOLt−IO
[Equation 8]
For the time duration DT < t < TX,
IC−(t)=VOL(DT−t)+D(VS−VO)Lf−IO
[Equation 9]
And for the time duration TX < t < T,
ICO=−IO
[Equation 10]
If the capacitance is assumed to be ideal, the capacitor current will not decay even after the inductor current value is reduced to zero value. For that case, the waveforms for the capacitor and inductor current are shown in Fig. 4.
From Fig.4, it is clear that the value of the capacitor current is zero at time t=Ta and at t=Tb.
Equation 8 at time t =Ta gives,
0=VS−VOLTa−IO
⇒Ta=LIOVS−VO
[Equation 11]
And Equation 9 at time t=Tb gives,
0=VO(DT−Tb)L+D(VS−VO)Lf−IO
⇒Tb=DT−LIOVO+D(VS−VO)fVO
[Equation 12]
1>
Figure 4. Inductor Current and Capacitor Current respectively for the Discontinuous Conduction Mode
of the Buck Converter
The positive time interval for the charge accumulation i.e. Tb-Ta from Equations 11 and 12 is given by:
Tb−Ta=DVSfVO−LIOVSVO(VS−VO)
[Equation 13]
From Equation 6 and Equation 7 we can get,
Tb−Ta=2ξ√−ξ2f
[Equation 14]
From Fig.4, it is also clear that the maximum value of the capacitor current occurs at the time t=DT.
At t = DT,
IC(DT) = Ihp
From Equation 8 we can get,
Ihp=(2ξ√−1)IO
[Equation 15]
The charge accumulated is the integration of the capacitor current (area under the capacitor current from Ta to Tb) which is also given by the expression:
∆Q=C∆V [Equation 16]
Thus,
C∆V=12(2ξ√−ξ)(2ξ√−1)IO(12f)=VO(2−ξ√)24Rf
The ripples in the load due to the ripples in the capacitor are given by the following expression:
r=∆VVO=(2−ξ√)24Rf
Boost Converter
Circuit for the boost converter is shown in Fig. 5.
Figure 5. Circuit for Boost Converter
The waveform for the continuous conduction
mode is shown in Fig. 6. When it is in the discontinuous conduction
mode, the waveform is shown in Fig. 7.
We can assume that the inductor is connected to the load for the time Ty such that
IO =Y Iavg [Equation 17]
where
Y = Ty/T
Figure 6. Supply Current, Diode Current, Inductor Current and Inductor Voltage respectively (Boost Converter)
Figure 7. Inductor Current and Voltage for the Discontinuous Conduction Mode of Boost Converter
When the converter operates in the
steady-state condition, the energy at the start and at the end of the
cycle is the same. Thus, volt-time balance condition can be applied here
too.
From the figure and the volt-time balance condition it is clear that,
TON VS+(TX-TON).(VS-VC)=0
From Fig. 6, it is also evident that the value of the minimum and maximum currents are as follows:
Imin=0;
and
Thus, the average value of the inductor current is,
From Equation 17 we can get,
The duty cycle ratio of the buck converter for the continuous conduction mode is equal to
In the discontinuous conduction mode, the
duty cycle ratio of the boost converter is not only dependent on the
input and output voltages but it also depends on the inductance L, load
resistance R, and the switching frequency f.
The discontinuous inductance for the boost converter is,
Substituting this value of inductance in Equation 18 we can get,
Hence, the complete conversion ratio for
the boost converter in the discontinuous conduction mode is given by the
above expression.
Buck-Boost Converter
The circuit for the buck-boost converter
is shown in Fig. 8 and the related waveforms of the buck-boost converter
in the case of continuous conduction mode are shown in Fig. 9.
Figure 8. Circuit for the Buck-Boost Converter
Inductor is connected to the load during the switch-off period; where Y= (1-D).
Thus,
Figure 9. Supply Current, Diode Current, Inductor Current and
Inductor Voltage respectively (Buck-Boost Converter) in Continuous
Conduction Mode
Figure 10. Inductor Current and Inductor Voltage for the Discontinuous Conduction Mode
of the Buck-Boost Converter
Assume that the converter is operating in steady state; therefore, energy at the start up to the end of the cycle must be equal. Thus, volt-time balance condition is applied here.
Applying the volt-sec balance across the inductor using the Fig. 9,
VS TON + (TX - TON) (-VO) = 0
⇒VSDT−(TX−DT)VO=0
⇒TX=D(VS+VO)VOf
From the Fig. 9, it is also noticed that the value of the minimum and maximum currents are as follows:
Imin = 0
Imax=VSLTON=VSLfD
Thus, the average value of the inductor current is,
Iavg=YVOR=12ImaxTXT
⇒VOR=12VSDLfD(VS+VO)YVOff
In the discontinuous conduction mode of the buck-boost converter, the value of the duty cycle ratio is given by
D=VO2LfRYVS(VS+VO)−−−−−−−−−−−−−√
The duty cycle ratio of the buck-boost converter for the continuous conduction mode is equal to VOVO+VS.
In the case of the discontinuous conduction mode, the duty cycle ratio of the buck-boost converter is also dependent on the inductance L, load resistance R, and the switching frequency f.
The conversion ratio for the buck-boost converter is,
VOVS=Dξ√−D
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